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![]() QEMU's -m option can take fractional megabyte values, and lowest granularity seems to be 0x2000. For example, run qemu with amount of memory set to 100005k (0x61A9400): $ qemu-system-arm -machine virt -cpu cortex-a15 -m 100005k \ -bios denx/u-boot.bin -nographic => fdt addr $fdt_addr => fdt print /memory@40000000 memory@40000000 { reg = <0x00000000 0x40000000 0x00000000 0x061aa000>; device_type = "memory"; }; When LPAE is enabled, 1:1 mapping is created using 2 MB blocks. In case amount of memory provided to QEMU is not multiple of 2 MB, hang occurs during MMU initialization. How to reproduce: qemu-system-arm -machine virt -m 1058 -nographic -bios u-boot.bin - boots qemu-system-arm -machine virt -m 1057 -nographic -bios u-boot.bin - hangs DRAM: 1 GiB initcall: 60011df8 initcall: 60011904 New Stack Pointer is: 80fffe90 initcall: 60011a20 initcall: 60011bcc initcall: 60011bd4 initcall: 600119b4 Relocation Offset is: 22042000 Relocating to 82042000, new gd at 81001ed0, sp at 80fffe90 initcall: 60011b8c initcall: 82053ea0 initcall: 82053ea8 initcall: 60012040 (relocated to 82054040) dram_bank_mmu_setup: bank: 0 - hang here during mmu init - This patches rounds down to the nearest multiple of 2MB when CONFIG_ARMV7_LPAE=y. Fixes: 3fa914af82("arm: qemu: implement enable_caches()") Signed-off-by: Igor Opaniuk <igor.opaniuk@foundries.io> Reviewed-by: Oleksandr Suvorov <oleksandr.suvorov@foundries.io> |
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Makefile | ||
qemu-arm.c | ||
qemu-arm.env |