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efi_selftest: implement exception test for sandbox

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Provide a unit test that causes an illegal instruction to occur.

The test can be run with the following commands:

    => setenv efi_selftest exception
    => bootefi selftest

This might be the output:

    Executing 'exception'
    EFI application triggers exception.
    Illegal instruction
    pc = 0x1444d016, pc_reloc = 0xffffaa078e8dd016
    UEFI image [0x0000000000000000:0xffffffffffffffff] '/\selftest'
    UEFI image [0x000000001444b000:0x0000000014451fff] pc=0x2016 '/bug.efi'
    Resetting ...

It would tell us that the exception was triggered by an instruction
0x2016 bytes after the load address of the binary with filename /bug.efi.

Signed-off-by: Heinrich Schuchardt <xypron.glpk@gmx.de>
Reviewed-by: Simon Glass <sjg@chromium.org>
This commit is contained in:
Heinrich Schuchardt 2020-11-12 00:29:58 +01:00 • committed by Simon Glass
parent 3a5ec03578
commit 04cc7914f2
1 changed files with 2 additions and 0 deletions
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2
lib/efi_selftest/efi_selftest_miniapp_exception.c
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@ -33,6 +33,8 @@ efi_status_t EFIAPI efi_main(efi_handle_t handle,
asm volatile (".word 0xe7f7defb\n");
#elif defined(CONFIG_RISCV)
asm volatile (".word 0xffffffff\n");
#elif defined(CONFIG_SANDBOX)
asm volatile (".word 0xffffffff\n");
#elif defined(CONFIG_X86)
asm volatile (".word 0xffff\n");
#endif