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Disable PIE compilation option

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ARM TF does not work correctly if built with a version of gcc
that is configured to use PIE by default (e.g. Debian Stretch).

This patch identifies when such a version of gcc is being used
(by searching for --enable-default-pie) and adds -fno-PIE option
to TF_CFLAGS.

fixes arm-software/tf-issues#519

Change-Id: I2322122c49841746d35d152694e14f6f73beb0fd
Signed-off-by: David Cunado <david.cunado@arm.com>
Co-Authored-by: Evan Lloyd <evan.lloyd@arm.com>
Tested-by: Steve Capper <steve.capper@arm.com>
Tested-by: Alexei Fedorov <alexei.fedorov@arm.com>
This commit is contained in:
david cunado 2017-11-30 21:58:01 +00:00 • committed by David Cunado
parent 842c00eb44
commit f7ec31db2d
1 changed files with 7 additions and 0 deletions
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7
Makefile
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@ -160,6 +160,13 @@ TF_CFLAGS += $(CPPFLAGS) $(TF_CFLAGS_$(ARCH)) \
-ffreestanding -fno-builtin -Wall -std=gnu99 \
-Os -ffunction-sections -fdata-sections
GCC_V_OUTPUT := $(shell $(CC) -v 2>&1)
PIE_FOUND := $(findstring --enable-default-pie,${GCC_V_OUTPUT})
ifeq ($(PIE_FOUND),1)
TF_CFLAGS += -fno-PIE
endif
TF_LDFLAGS += --fatal-warnings -O1
TF_LDFLAGS += --gc-sections
TF_LDFLAGS += $(TF_LDFLAGS_$(ARCH))